3.2.32 \(\int \frac {(a x^2+b x^3)^2}{x} \, dx\)

Optimal. Leaf size=30 \[ \frac {a^2 x^4}{4}+\frac {2}{5} a b x^5+\frac {b^2 x^6}{6} \]

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Rubi [A]  time = 0.02, antiderivative size = 30, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.118, Rules used = {1584, 43} \begin {gather*} \frac {a^2 x^4}{4}+\frac {2}{5} a b x^5+\frac {b^2 x^6}{6} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(a*x^2 + b*x^3)^2/x,x]

[Out]

(a^2*x^4)/4 + (2*a*b*x^5)/5 + (b^2*x^6)/6

Rule 43

Int[((a_.) + (b_.)*(x_))^(m_.)*((c_.) + (d_.)*(x_))^(n_.), x_Symbol] :> Int[ExpandIntegrand[(a + b*x)^m*(c + d
*x)^n, x], x] /; FreeQ[{a, b, c, d, n}, x] && NeQ[b*c - a*d, 0] && IGtQ[m, 0] && ( !IntegerQ[n] || (EqQ[c, 0]
&& LeQ[7*m + 4*n + 4, 0]) || LtQ[9*m + 5*(n + 1), 0] || GtQ[m + n + 2, 0])

Rule 1584

Int[(u_.)*(x_)^(m_.)*((a_.)*(x_)^(p_.) + (b_.)*(x_)^(q_.))^(n_.), x_Symbol] :> Int[u*x^(m + n*p)*(a + b*x^(q -
p))^n, x] /; FreeQ[{a, b, m, p, q}, x] && IntegerQ[n] && PosQ[q - p]

Rubi steps

\begin {align*} \int \frac {\left (a x^2+b x^3\right )^2}{x} \, dx &=\int x^3 (a+b x)^2 \, dx\\ &=\int \left (a^2 x^3+2 a b x^4+b^2 x^5\right ) \, dx\\ &=\frac {a^2 x^4}{4}+\frac {2}{5} a b x^5+\frac {b^2 x^6}{6}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 30, normalized size = 1.00 \begin {gather*} \frac {a^2 x^4}{4}+\frac {2}{5} a b x^5+\frac {b^2 x^6}{6} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(a*x^2 + b*x^3)^2/x,x]

[Out]

(a^2*x^4)/4 + (2*a*b*x^5)/5 + (b^2*x^6)/6

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IntegrateAlgebraic [A]  time = 0.02, size = 30, normalized size = 1.00 \begin {gather*} \frac {a^2 x^4}{4}+\frac {2}{5} a b x^5+\frac {b^2 x^6}{6} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(a*x^2 + b*x^3)^2/x,x]

[Out]

(a^2*x^4)/4 + (2*a*b*x^5)/5 + (b^2*x^6)/6

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fricas [A]  time = 0.39, size = 24, normalized size = 0.80 \begin {gather*} \frac {1}{6} \, b^{2} x^{6} + \frac {2}{5} \, a b x^{5} + \frac {1}{4} \, a^{2} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a*x^2)^2/x,x, algorithm="fricas")

[Out]

1/6*b^2*x^6 + 2/5*a*b*x^5 + 1/4*a^2*x^4

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giac [A]  time = 0.17, size = 24, normalized size = 0.80 \begin {gather*} \frac {1}{6} \, b^{2} x^{6} + \frac {2}{5} \, a b x^{5} + \frac {1}{4} \, a^{2} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a*x^2)^2/x,x, algorithm="giac")

[Out]

1/6*b^2*x^6 + 2/5*a*b*x^5 + 1/4*a^2*x^4

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maple [A]  time = 0.04, size = 25, normalized size = 0.83 \begin {gather*} \frac {1}{6} b^{2} x^{6}+\frac {2}{5} a b \,x^{5}+\frac {1}{4} a^{2} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^3+a*x^2)^2/x,x)

[Out]

1/4*a^2*x^4+2/5*a*b*x^5+1/6*b^2*x^6

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maxima [A]  time = 1.27, size = 24, normalized size = 0.80 \begin {gather*} \frac {1}{6} \, b^{2} x^{6} + \frac {2}{5} \, a b x^{5} + \frac {1}{4} \, a^{2} x^{4} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^3+a*x^2)^2/x,x, algorithm="maxima")

[Out]

1/6*b^2*x^6 + 2/5*a*b*x^5 + 1/4*a^2*x^4

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mupad [B]  time = 0.03, size = 24, normalized size = 0.80 \begin {gather*} \frac {a^2\,x^4}{4}+\frac {2\,a\,b\,x^5}{5}+\frac {b^2\,x^6}{6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a*x^2 + b*x^3)^2/x,x)

[Out]

(a^2*x^4)/4 + (b^2*x^6)/6 + (2*a*b*x^5)/5

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sympy [A]  time = 0.07, size = 26, normalized size = 0.87 \begin {gather*} \frac {a^{2} x^{4}}{4} + \frac {2 a b x^{5}}{5} + \frac {b^{2} x^{6}}{6} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**3+a*x**2)**2/x,x)

[Out]

a**2*x**4/4 + 2*a*b*x**5/5 + b**2*x**6/6

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